10x^2=0.1

Solution for 10x^2=0.1 equation:

10x^2=0.1

We move all terms to the left:

10x^2-(0.1)=0

We add all the numbers together, and all the variables

10x^2-0.1=0

a = 10; b = 0; c = -0.1;
Δ = b2-4ac
Δ = 02-4·10·(-0.1)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2}{2*10}=\frac{-2}{20}
=-1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2}{2*10}=\frac{2}{20}
=1/10
$